a)|x|-9=-2+17

   |x|-9 = 15

   |x|     = 15 + 9

   |x|      = 24

\(\Rightarrow x=\mp24\)

b)|x-9|=-2+17

    |x-9| = 15

\(\Rightarrow\orbr{\begin{cases}x-9=15\\x-9=-15\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=24\\x=-6\end{cases}}\)

Hok tốt !

a)|x|-9=-2+17

| x| -9 = 15

| x | = 15 + 9

| x| = 24

Vậy x= 24 hoặc x = -24

b)|x-9|=-2+17

| x -9| = 15

Th1: x - 9 = 15

x = 15 + 9

x = 24

Th2 : x - 9 = -15

x = -15 + 9

x = -6

vậy x = 24 hoặcx = -6

hok tốt!!!

                                                          Bài giải

a, \(\left|x\right|-9=-2+17\)

\(\left|x\right|-9=15\)

\(\left|x\right|=15+9\)

\(\left|x\right|=24\)

\(x\in\left\{\pm24\right\}\)

b, \(\left|x-9\right|=-2+17\)

\(\left|x-9\right|=15\)

\(\Rightarrow\orbr{\begin{cases}x-9=-15\\x-9=15\end{cases}}\Rightarrow\orbr{\begin{cases}x=-6\\x=24\end{cases}}\)

\(\Rightarrow\text{ }x\in\left\{-6\text{ ; }24\right\}\)

\(\dfrac{x}{15}\)+\(\dfrac{x}{12}\)=4/1+1/2=9/2

=>x(\(\dfrac{1}{15}\)+\(\dfrac{1}{12}\))=9/2

=>x\(\cdot\)\(\dfrac{3}{20}\)=9/2

=>x=9/2:3/20=30

Vậy x=30

\(\dfrac{x}{15}+\dfrac{x}{12}=\dfrac{9}{2}\Rightarrow\left(\dfrac{1}{15}+\dfrac{1}{12}\right)x=\dfrac{9}{2}\)

\(\Rightarrow\left(\dfrac{12+18}{180}\right)x=\dfrac{9}{2}\Rightarrow\dfrac{30}{180}x=\dfrac{9}{2}\Rightarrow\dfrac{1}{6}x=\dfrac{9}{2}\Rightarrow x=\dfrac{9}{2}.6=27\)

2/5 + x = 15/20

2/5 + x = 3/4

x = 3/4 - 2/5 

x = 7/20

8/9 - 2/9 : x = 2/3

2/9 : x = 8/9 - 2/3 

2/9 : x = 2/9

x = 2/9 : 2/9

x = 1

\(\frac{2}{5}+x=\frac{15}{20}\)

\(\frac{2}{5}+x=\frac{3}{4}\)

\(x=\frac{3}{4}-\frac{2}{5}\)

\(x=\frac{7}{20}\)

\(\frac{8}{9}-\frac{2}{9}:x=\frac{2}{3}\)

\(\frac{2}{9}:x=\frac{8}{9}-\frac{2}{3}\)

\(\frac{2}{9}:x=\frac{2}{9}\)

\(x=\frac{2}{9}:\frac{2}{9}\)

\(x=1\)

Mik làm chi tiết nhé, bạn có thể lược 1 số phần nếu thích

\(\frac{2}{5}+x=\frac{15}{20}\)

=>\(\frac{2}{5}+x=\frac{3}{5}\)

=>\(x=\frac{3}{5}-\frac{2}{5}\)

=> \(x=\frac{1}{5}\)

\(\frac{8}{9}-\frac{2}{9}:x=\frac{2}{3}\)

=> \(\frac{8}{9}-\frac{2}{9}:x=\frac{6}{9}\)

=> \(\frac{2}{9}:x=\frac{8}{9}-\frac{6}{9}\)

=>\(\frac{2}{9}:x=\frac{2}{9}\)

=> \(x=\frac{2}{9}:\frac{2}{9}\)

=> \(x=1\)

\(\dfrac{-3}{5}-x=\dfrac{21}{10}\)

\(x=\dfrac{-3}{5}-\dfrac{21}{10}\)

\(x=\)-\(\dfrac{27}{10}\)

\(x:\dfrac{2}{9}=\dfrac{9}{2}\)

\(x.\dfrac{9}{2}=\dfrac{9}{2}\)

\(x=\dfrac{9}{2}:\dfrac{9}{2}\)

\(x=1\)

\(\dfrac{x}{9}=\dfrac{5}{3}\)

\(x.3=5.9\)

\(x.3=45\)

\(x=45:3=15\)

\(x:\left(\dfrac{2}{5}\right)^3=\left(\dfrac{5}{2}\right)^3\)

\(x:\dfrac{8}{125}=\dfrac{125}{8}\)

\(x.\dfrac{125}{8}=\dfrac{125}{8}\)

\(x=\dfrac{125}{8}:\dfrac{125}{8}=1\)

\(\sqrt{x^2-2x+4}+\sqrt{x^2+5}=9-2x\left(đk:x\le\dfrac{9}{2}\right)\)

\(\Leftrightarrow x^2-2x+4+x^2+5+2\sqrt{\left(x^2-2x+4\right)\left(x^2+5\right)}=81-36x+4x^2\)

\(\Leftrightarrow2\sqrt{\left(x^2-2x+4\right)\left(x^2+5\right)}=2x^2-34x+72\)

\(\Leftrightarrow4\left(x^2-2x+4\right)\left(x^2+5\right)=4x^4+1156x^2+5184-136x^3+288x^2-4896x\)

\(\Leftrightarrow4x^4-8x^3+36x^2-40x+80=4x^4-136x^3+1444x^2-4896x+5184\)

\(\Leftrightarrow128x^3-1408x^2+4856x-5104=0\)

\(\Leftrightarrow128x^2\left(x-2\right)-1152x\left(x-2\right)+2552\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(128x^2-1152x+2552\right)=0\)

\(\Leftrightarrow x=2\left(tm\right)\)(do \(128x^2-1152x+2552>0\))

a: \(x+\dfrac{3}{9}=\dfrac{7}{6}\cdot\dfrac{2}{3}\)

=>\(x+\dfrac{1}{3}=\dfrac{14}{18}=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}-\dfrac{1}{3}=\dfrac{7}{9}-\dfrac{3}{9}=\dfrac{4}{9}\)

b: \(x-\dfrac{2}{3}=\dfrac{1}{8}:\dfrac{5}{4}\)

=>\(x-\dfrac{2}{3}=\dfrac{1}{8}\cdot\dfrac{4}{5}=\dfrac{1}{10}\)

=>\(x=\dfrac{1}{10}+\dfrac{2}{3}=\dfrac{3+20}{30}=\dfrac{23}{30}\)

\(\Rightarrow9\left(x-1\right)^2-2=\dfrac{1}{4}\\ \Rightarrow9\left(x-1\right)^2=\dfrac{9}{4}\\ \Rightarrow\left(x-1\right)^2=4\\ \Rightarrow\left[{}\begin{matrix}x-1=2\\1-x=2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

\(a,2^{x+1}=64\\ \Rightarrow a,2^{x+1}=2^6\\ \Rightarrow x+1=6\\ \Rightarrow x=5\)

\(b,x=18\)

\(c,\left(4x-9\right)-\left(x+111\right)=0\\ \Rightarrow4x-9-x-111=0\\ \Rightarrow3x-120=0\\ \Rightarrow3x=120\\ \Rightarrow x=40\)

a
,
2
x
+
1
=
64
⇒
a
,
2
x
+
1
=
2
6
⇒
x
+
1
=
6
⇒
x
=
5

b
,
x
=
18

c
,
(
4
x
−
9
)
−
(
x
+
111
)
=
0
⇒
4
x
−
9
−
x
−
111
=
0
⇒
3
x
−
120
=
0
⇒
3
x
=
120
⇒
x
=
40

=x+2/x(x+3)-x+1/(x+3)(x-3)

=(x+2)(x-3)/x(x+3)(x-3)-(x+1)x/x(x-3)(x+3)

=(x+2)(x-3)-x(x+1)/x(x-3)(x+3)

=x^2-x-6-x^2-x/x(x-3)(x+3)

=-2x-6/x(x-3)(x+3)

=-2(x+3)/x(x-3)(x+3)

=-2/x(x-3)

Thế thì bằng 362880

Sửa lại nè :

2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 

= 326 880

Hok tốt

= 362880 nhuhu